10(x^2)+12x+4=20

Solution for 10(x^2)+12x+4=20 equation:

Simplifying
10(x2) + 12x + 4 = 20

Reorder the terms:
4 + 12x + 10x2 = 20

Solving
4 + 12x + 10x2 = 20

Solving for variable 'x'.

Reorder the terms:
4 + -20 + 12x + 10x2 = 20 + -20

Combine like terms: 4 + -20 = -16
-16 + 12x + 10x2 = 20 + -20

Combine like terms: 20 + -20 = 0
-16 + 12x + 10x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-8 + 6x + 5x2) = 0

Factor a trinomial.
2((-2 + -1x)(4 + -5x)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-2 + -1x)' equal to zero and attempt to solve:

Simplifying
-2 + -1x = 0

Solving
-2 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1x = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1x = 0 + 2
-1x = 0 + 2

Combine like terms: 0 + 2 = 2
-1x = 2

Divide each side by '-1'.
x = -2

Simplifying
x = -2
Subproblem 2
Set the factor '(4 + -5x)' equal to zero and attempt to solve:

Simplifying
4 + -5x = 0

Solving
4 + -5x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -5x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -5x = 0 + -4
-5x = 0 + -4

Combine like terms: 0 + -4 = -4
-5x = -4

Divide each side by '-5'.
x = 0.8

Simplifying
x = 0.8
Solution
x = {-2, 0.8}